2[d-(2d+15)+13]=2(d+2)

Solution for 2[d-(2d+15)+13]=2(d+2) equation:

Simplifying
2[d + -1(2d + 15) + 13] = 2(d + 2)

Reorder the terms:
2[d + -1(15 + 2d) + 13] = 2(d + 2)
2[d + (15 * -1 + 2d * -1) + 13] = 2(d + 2)
2[d + (-15 + -2d) + 13] = 2(d + 2)

Reorder the terms:
2[-15 + 13 + d + -2d] = 2(d + 2)

Combine like terms: -15 + 13 = -2
2[-2 + d + -2d] = 2(d + 2)

Combine like terms: d + -2d = -1d
2[-2 + -1d] = 2(d + 2)
[-2 * 2 + -1d * 2] = 2(d + 2)
[-4 + -2d] = 2(d + 2)

Reorder the terms:
-4 + -2d = 2(2 + d)
-4 + -2d = (2 * 2 + d * 2)
-4 + -2d = (4 + 2d)

Solving
-4 + -2d = 4 + 2d

Solving for variable 'd'.

Move all terms containing d to the left, all other terms to the right.

Add '-2d' to each side of the equation.
-4 + -2d + -2d = 4 + 2d + -2d

Combine like terms: -2d + -2d = -4d
-4 + -4d = 4 + 2d + -2d

Combine like terms: 2d + -2d = 0
-4 + -4d = 4 + 0
-4 + -4d = 4

Add '4' to each side of the equation.
-4 + 4 + -4d = 4 + 4

Combine like terms: -4 + 4 = 0
0 + -4d = 4 + 4
-4d = 4 + 4

Combine like terms: 4 + 4 = 8
-4d = 8

Divide each side by '-4'.
d = -2

Simplifying
d = -2